DMSO-d
6 was used as the solvent in the NMR experiments because of its good solubility for PhT, PhB, and PA. PA was used as the internal standard because its NMR signals do not overlap with those of analytes in the
1H NMR spectrum. The NMR spectra of analytes, internal standard, their mixture, and PhT compound tablet in DMSO-d
6 are shown in
Figure 2. As shown in
Figure 3, the signal at δ 7.30 ppm assigned to the phenyl groups of PhB (5H, s) and PhT (10H, s), which completely overlap, and the signal at δ 0.79 ppm (3H, t), belonging to the methyl group of PhB, which do not overlap with any other signals, were selected as the analytical signal for quantitative purposes. The
1H NMR spectrum of PA exhibited the characteristic signal of 2 aromatic protons at δ 8.57 ppm (2H, s, H-3, H-5;
Figure 3, signal A). This well-resolved aromatic signal is suitable for quantification. From these data, 3 signals at δ 0.79, 7.30, and 8.57 ppm were used to quantify the PhB and PhT mixture through qNMR. The PhB methyl signal was used to quantify it (
Figure 3, signal C). However, there is an overlap problem for the PhT measurement, and no well-separated signal is obtained. PhT produces only 1 non-exchangeable hydrogen signal, which is located in the aromatic region and overlaps with the PhB signal (
Figure 3, signal B). Therefore, considering the 3 to 5 ratio of hydrogens of the methyl group to the hydrogens of the phenyl group of PhB and determining the share of PhB from the integral of the aromatic region signal, the share of PhT could be calculated and used to calculate its amount. The following equations have been used: